Simon Dalton presents his prediction for the Australian Open match.
Alex de Minaur, the top-ranked Australian and world number eight, consistently delivers strong performances in Melbourne, having reached the fourth round consistently since 2022. He remains unbeaten this season (3-0), and his winning streak, including last year, now stands at eight matches. Tristan Boyer, making his debut in the main draw of a Grand Slam, has already achieved his primary goal of edging closer to the top 100, but now he faces a formidable challenge against a strong opponent.
Tristan Boyer
Boyer continues his nine-match winning streak, but his first-round performance against Federico Coria (6:7, 6:4, 3:6, 7:6, 6:3) raises questions. The American was the clear favourite, but he was pushed to a fifth set and nearly eliminated when Coria served for the match in the fourth set. Boyer's playing style is aggressive—he hit 58 winners but also committed 54 unforced errors in the first round, highlighting his inconsistency. He thrives at the Challenger level but has never faced opponents ranked even in the top 50.
Alex de Minaur
The Australian confidently dispatched Botic van de Zandschulp in the opening round (6:1, 7:5, 6:4). Despite minor challenges in the second set, de Minaur controlled the match, winning 76% of points on his first serve and hitting 13 aces. He traditionally leaves little chance for opponents outside the top 100, securing 18 wins in his last 20 encounters, and he triumphs over such opponents on hard court Grand Slams 89% of the time. At the Australian Open, he consistently dominates lower-ranked players, defeating the likes of Flavio Cobolli, Benjamin Bonzi, Botic van de Zandschulp, and Matteo Arnaldi by more than eight games in 2023-24.
Tristan Boyer vs Alex de Minaur Prediction
Alex De Minaur holds a significant advantage in class and consistency. Boyer may bring aggressive tennis, but he has yet to face top-ranked players. The Australian regularly overwhelms such opponents in Melbourne, so we back a win for Alex de Minaur.